7x^2-5x-92=0

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Solution for 7x^2-5x-92=0 equation: 



7x^2-5x-92=0

a = 7; b = -5; c = -92;
Δ = b2-4ac
Δ = -52-4·7·(-92)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-51}{2*7}=\frac{-46}{14}
=-3+2/7
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+51}{2*7}=\frac{56}{14}
=4
$

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